f^2=196f2=196

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Solution for f^2=196f2=196 equation: 



f^2=196f^2=196

We move all terms to the left:

f^2-(196f^2)=0

We add all the numbers together, and all the variables

-195f^2=0

a = -195; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-195)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$f=\frac{-b}{2a}=\frac{0}{-390}=0$

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